Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Il | 5583 | 187 | 1 | 187.0000 |
Cette | 1825 | 162 | 1 | 162.0000 |
En | 3015 | 161 | 1 | 161.0000 |
Ces | 1147 | 95 | 1 | 95.0000 |
La | 7433 | 605 | 7 | 86.4286 |
Elle | 1581 | 76 | 1 | 76.0000 |
Pour | 2429 | 122 | 2 | 61.0000 |
Mais | 1364 | 55 | 1 | 55.0000 |
Le | 8474 | 581 | 11 | 52.8182 |
Les | 7738 | 624 | 13 | 48.0000 |
Ce | 2183 | 131 | 3 | 43.6667 |
Cela | 369 | 35 | 1 | 35.0000 |
Depuis | 404 | 32 | 1 | 32.0000 |
Au | 865 | 61 | 2 | 30.5000 |
Nous | 1482 | 87 | 3 | 29.0000 |
Cet | 295 | 26 | 1 | 26.0000 |
Comme | 342 | 25 | 1 | 25.0000 |
Des | 907 | 72 | 3 | 24.0000 |
Et | 1024 | 47 | 2 | 23.5000 |
Ils | 1023 | 46 | 2 | 23.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
d | 24359 | 1 | 1240 | 0.0008 |
l | 28543 | 1 | 262 | 0.0038 |
qu | 4176 | 1 | 176 | 0.0057 |
s | 4522 | 1 | 96 | 0.0104 |
n | 4097 | 3 | 82 | 0.0366 |
j | 863 | 1 | 24 | 0.0417 |
aujourd | 424 | 1 | 15 | 0.0667 |
L | 4188 | 1 | 14 | 0.0714 |
c | 1841 | 2 | 27 | 0.0741 |
beau | 114 | 1 | 12 | 0.0833 |
M | 498 | 1 | 11 | 0.0909 |
m | 651 | 3 | 32 | 0.0938 |
t | 128 | 1 | 9 | 0.1111 |
rubrique | 139 | 1 | 9 | 0.1111 |
dans | 14084 | 84 | 703 | 0.1195 |
paragraphe | 43 | 1 | 8 | 0.1250 |
jusqu | 638 | 1 | 8 | 0.1250 |
profil | 82 | 1 | 7 | 0.1429 |
entend | 61 | 1 | 7 | 0.1429 |
te | 139 | 1 | 7 | 0.1429 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II